0  B19R0.149  CCCCCCCC\C=C/CCCCCCCC(=O)O DB06689 [2,0,0,0,0,0|1,0,0]=3
1  B19R0.149  CCCCCCCC\C=C\CCCCCCCC(=O)O DB04224 [2,0,0,0,0,0|1,0,0]=3
2  B19R0.149  CCCCCCCC\C=C\CCCCCCCC(N)=O DB03784 [2,0,0,0,0,0|0,0,0]=2