0  B32R4.2726800817  [C@@H]12CCC3=CC(=O)C=C[C@]3(C)[C@H]1[C@@H](O)C[C@@]4(C)[C@H]2CC[C@]4(O)C(=O)COC(C)=O HY-B1214 [1,1,0,0,0,0|0,1,1]=4