0  B12R0.812  N#C[Fe-4](C#N)(C#N)(C#N)(C#N)C#N DB06783 [0,0,0,0,0,0|0,0,0]=0
1  B12R0.812  O=N[Fe-2](C#N)(C#N)(C#N)(C#N)C#N DB00325 [0,0,0,0,0,0|2,0,0]=2