0  B19R0.149  CCCCCCCC/C=C\CCCCCCCC(O)=O DB06689 [1,0,0,0,0,0|0,0,3]=4
1  B19R0.149  CCCCCCCCCCCCCCCCCC(O)=O DB03193 [1,0,0,0,0,0|0,0,1]=2