0  B17R0.43  CCCCCCCCCCCCCCCC(=O)O DB03796 [0,0,1,0,0,0|0,0,0]=1
1  B17R0.43  CCCCCC\C=C/CCCCCCCC(=O)O DB04257 [0,0,1,0,0,0|0,0,2]=3
2  B16R0.303  CCCCCCCCCCCCCCCC=O DB03381 [1,0,1,0,0,0|0,0,0]=2
3  B16R0.303  CCCCCCCCCCCCCCCCO DB09494 [1,0,1,0,0,0|0,0,1]=3