0  B16R2.252  ClC1=NC(NCC2=CC=CC=C2)=NC=C1 O12019 [1,0,0,0,0,0|3,0,0]=4
1  B15R2.94  NC1=CC(C2=CC=CC=C2)=NNC1=O 57029 [0,0,0,0,2,0|2,0,0]=4