0  B16R2.252  NC1=NC=NC(SCC2=CC=CC=C2)=N1 BB52-6397 [1,0,0,0,0,0|3,0,0]=4
1  B15R2.283  NC1=NC(CCC2=CC=CC=C2)=NN1 BB52-7340 [1,0,0,0,1,0|2,0,0]=4
2  B15R2.283  NC1=NC(SCC2=CC=CC=C2)=NN1 BB52-6661 [1,0,0,0,1,0|1,0,0]=3