0  B15R2.3  FC1=CC=C(C2=NC=C(Br)C=C2)C=C1 D86672 [1,0,0,0,1,0|2,0,0]=4
1  B15R2.98  FC1=CC=C(CC2=CC=C(I)S2)C=C1 37627 [1,0,0,0,1,0|2,0,0]=4
2  B15R2.28  NC1=CC(C2=CC=C(F)C=C2)=NC=C1 78706 [1,0,0,0,1,0|2,0,0]=4