0  B16R2.132  Brc1ccc(nc1)NCC2CCOCC2 1P01BBPF [1,0,0,0,0,0|3,0,0]=4
1  B15R2.29  O=c1ccc(c[nH]1)CC2CCNCC2 1P00J3CF [1,0,0,0,1,0|2,0,0]=4