0  B12R2.612  OB1OCC2=CC(F)=CC=C12 B03-0225 [0,0,0,0,0,0|3,1,0]=4
1  B12R2.612  OB1OCC2=NC(Cl)=CC=C12 B01-0241 [0,0,0,0,0,0|4,0,0]=4
2  B10R1.13  OB(O)c1ccc(Cl)nc1 B01-0002 [1,0,1,0,0,0|2,0,0]=4
3  B10R1.13  OB(O)c1ccc(F)cc1 B03-0011 [1,0,1,0,0,0|1,1,0]=4