0  B16R2.132  NC1=NNC(CCC2=CC=CC=C2)=NN1 BB52-7904 [1,0,0,0,0,0|3,0,0]=4
1  B16R2.132  SC1=NNC(CCC2=CC=CC=C2)=NN1 BB52-7879 [1,0,0,0,0,0|2,1,0]=4