0  B21R0.81  CCCCCCCCCCCCCCCCCCCC(N)=O BB31-4903 [1,0,0,0,0,0|3,0,0]=4
1  B21R0.81  O=C(O)CCCCCCCCCCCCCCCCCCBr BB31-8673 [1,0,0,0,0,0|3,0,0]=4
2  B20R0.2932  CCCCCCCCCCCCCCCCCCCC=O BB32-1159 [2,0,0,0,0,0|2,0,0]=4