0 B15R2.15371 c1cc(c(c(c1)Cl)NC2=NCCN2)Cl BC204172 [0,0,0,0,0,0|1,0,0]=1 1 B13R2.18 c1ccc(c(c1)C2CCCN2)Cl BC227875 [1,0,0,0,1,0|1,0,1]=4