0  B15R2.283  NC1=NC(COC2=CC=CC=C2)=NN1 BB52-7341 [0,1,0,0,0,0|2,0,0]=3
1  B15R2.283  NC1=NC(SCC2=CC=CC=C2)=NN1 BB52-6661 [0,1,0,0,0,0|3,0,0]=4