0 B13R2.10 CC1=CNC(C2=CC=CC=C2)=N1 M10021530P [0,0,0,0,0,0|3,0,1]=4 1 B13R2.10 NC1=CN(C2=CC=CC=C2)C=N1 M10786714P [0,0,0,0,0,0|3,0,1]=4 2 B13R2.10 NC1=NN=C(C2=CC=CC=C2)S1 M10038850P [0,0,0,0,0,0|3,0,1]=4 3 B12R2.2 C1(C2=CC=CC=C2)=CNC=N1 M10018045P [1,0,0,0,0,0|1,0,2]=4 4 B12R2.2 C1(C2=CC=CC=C2)=NC=CN1 M10018046P [1,0,0,0,0,0|2,0,1]=4 5 B14R2.20 O=C1NCC(C2=CC=C(Cl)C=C2)C1 M10175543P [0,1,0,0,0,0|3,0,0]=4 6 B14R2.598 O=C1O[C@H](C2=CC=CC=C2)[C@H](C)N1 M10141652P [0,1,0,0,0,0|3,0,0]=4 7 B12R1.27 CCC(OCC1=CC=CC=C1)=O M10004505P [0,0,1,0,0,0|3,0,0]=4 8 B12R1.27 O=C(OC)CNC1=CC=CC=C1 M10121939P [0,0,1,0,0,0|3,0,0]=4 9 B12R1.27 O=C(OC)COC1=CC=CC=C1 M10039630P [0,0,1,0,0,0|3,0,0]=4 10 B12R1.107 CC(OC(C1=CC=CC=C1)C)=O M10002262P [0,0,1,0,0,0|2,0,1]=4 11 B12R1.107 O=C(O)CN(C)C1=CC=CC=C1 M10172364P [0,0,1,0,0,0|3,0,0]=4 12 B12R1.107 O=C(O)CN(C)C1=CC=CC=C1 M10243459P [0,0,1,0,0,0|3,0,0]=4 13 B12R1.252 O=C([O-])CCCC1=CC=CC=C1 M10035233P [0,0,1,0,0,0|3,0,0]=4 14 B14R2.19 S=C1OC[C@@H](CC2=CC=CC=C2)N1 M10821511P [0,0,0,0,0,1|1,0,1]=3 15 B14R2.19 S=C1OC[C@H](CC2=CC=CC=C2)N1 M10768680P [0,0,0,0,0,1|1,0,1]=3 16 B14R2.21 O=C1CC(C2=CC=CC=C2)CCC1 M10167473P [0,0,0,0,0,1|3,0,0]=4 17 B14R2.21 O=C1NC(C2=CC=CC=C2)CCC1 M10245848P [0,0,0,0,0,1|2,0,1]=4 18 B14R2.68 NC1=NC=C(C2=CC=CC=C2)N=C1 M10124627P [0,0,0,0,0,1|1,0,2]=4 19 B11R1.12 CO[C@H](C1=CC=CC=C1)CO M10150609P [1,0,1,0,0,0|1,0,1]=4 20 B11R1.16 C[C@@H](C1=CC=CC=C1)N=C=O M10132504P [1,0,1,0,0,0|0,0,2]=4 21 B11R1.16 C[C@H](C1=CC=CC=C1)N=C=O M10220208P [1,0,1,0,0,0|0,0,2]=4 22 B11R1.91 S\C(N)=N\CC1=CC=CC=C1 M10013542P [1,0,1,0,0,0|0,1,0]=3 23 B13R2.373 O=C1N[C@@H](C2=CC=CC=C2)[C@H]1O M10734473P [0,1,0,0,1,0|1,0,1]=4 24 B15R2.275 NCC1=NC(C2=CC=C(F)C=C2)=NO1 M10084722P [0,2,0,0,0,0|1,0,1]=4 25 B13R2.72 O=C(C1CCC2=C1C=CC=C2)N M10221350P [0,0,1,1,0,0|2,0,0]=4 26 B11R1.40 CCC(CC1=CC=CC=C1)=O M10025082P [0,0,1,0,1,0|2,0,0]=4 27 B11R2.239 C1(C2=CC=CC=C2)CNC1 M10109190P [1,0,0,0,1,0|1,0,1]=4 28 B11R2.239 C1(C2=CC=CC=C2)COC1 M10114041P [1,0,0,0,1,0|0,0,1]=3 29 B11R2.239 C1(C2=CC=CC=C2)NCC1 M10175940P [1,0,0,0,1,0|0,0,2]=4 30 B13R1.337 O=C(Cl)OCCOC1=CC=CC=C1 M10224839P [0,0,1,0,0,1|2,0,0]=4