0  B16R0.303  CCCCCCCCCCCCCCCCF 1100-3-40 [0,0,1,0,0,0|2,0,1]=4
1  B15R0.70  BrCCCCCCCCCCCCCCBr 1100-9-X6 [1,0,1,0,0,0|2,0,0]=4
2  B15R0.70  C=CCCCCCCCCCCCCCC 1300-1-16 [1,0,1,0,0,0|1,0,0]=3
3  B17R0.43  O=C(O)CCCCCCCCCCCCCCO 2129-1-X3 [0,1,1,0,0,0|0,0,0]=2