0 B4R0.1 C=C(Br)CBr SBB061691 [0,0,0,0,0,0|1,2,1]=4 1 B4R0.1 CC(Br)CCl SBB061477 [0,0,0,0,0,0|1,1,2]=4 2 B4R0.1 CC(Cl)CCl SBB059979 [0,0,0,0,0,0|1,0,2]=3 3 B4R0.1 COC(=N)N SBB067236 [0,0,0,0,0,0|4,0,0]=4 4 B4R0.1 CSC(=N)N SBB080624 [0,0,0,0,0,0|4,0,0]=4 5 B4R0.1 CSC(=N)N SBB095512 [0,0,0,0,0,0|4,0,0]=4 6 B4R0.1 ClC(Br)CBr SBB059976 [0,0,0,0,0,0|0,2,2]=4 7 B4R0.1 N=C(N)CCl SBB056491 [0,0,0,0,0,0|2,0,1]=3 8 B4R0.1 NCC(=O)O SBB071447 [0,0,0,0,0,0|3,0,1]=4 9 B4R0.1 NCC(=O)[O-] SBB116671 [0,0,0,0,0,0|3,0,1]=4 10 B4R0.1 NNC(N)=S SBB040860 [0,0,0,0,0,0|4,0,0]=4 11 B4R0.1 O=C(Br)CBr SBB040828 [0,0,0,0,0,0|1,2,1]=4 12 B4R0.1 O=C(Cl)CBr SBB051682 [0,0,0,0,0,0|1,1,1]=3 13 B4R0.1 O=C(Cl)CCl SBB040859 [0,0,0,0,0,0|1,0,1]=2 14 B4R0.1 O=C(O)CBr SBB053569 [0,0,0,0,0,0|2,1,1]=4 15 B4R0.1 [NH2+]=C(N)SC SBB060409 [0,0,0,0,0,0|4,0,0]=4 16 B4R0.1 [NH3+]NC(=N)N SBB059784 [0,0,0,0,0,0|4,0,0]=4 17 B4R0.1 [NH3+]NC(N)=O SBB060865 [0,0,0,0,0,0|4,0,0]=4 18 B3R0.1 C=CCBr SBB059929 [1,0,0,0,0,0|1,1,1]=4 19 B3R0.1 C\C=C\Cl SBB059896 [1,0,0,0,0,0|1,0,0]=2 20 B3R0.1 ClCCCl SBB040805 [1,0,0,0,0,0|0,0,2]=3 21 B3R0.1 NCCCl SBB005775 [1,0,0,0,0,0|1,0,2]=4 22 B3R0.2 N=C(N)N SBB065761 [1,0,0,0,0,0|3,0,0]=4 23 B3R0.2 NC(N)=O SBB008449 [1,0,0,0,0,0|3,0,0]=4 24 B5R0.1 CC(C)=CCBr SBB061690 [0,1,0,0,0,0|2,1,0]=4 25 B5R0.1 CCCC(=O)Cl SBB040624 [0,1,0,0,0,0|2,0,1]=4 26 B5R0.1 CCOC(=O)Cl SBB040861 [0,1,0,0,0,0|2,0,1]=4 27 B5R0.1 C\C(Cl)=C\CN SBB301293 [0,1,0,0,0,0|2,0,0]=3 28 B5R0.1 C\C(N)=C\C#N SBB002655 [0,1,0,0,0,0|3,0,0]=4 29 B5R0.1 O=C(O)CCCl SBB069140 [0,1,0,0,0,0|2,0,1]=4 30 B5R0.3 C=C(CCl)CCl SBB061694 [0,1,0,0,0,0|1,0,1]=3 31 B5R0.3 C=CC(Cl)CCl SBB060215 [0,1,0,0,0,0|1,0,1]=3 32 B5R0.3 CCC(Cl)CCl SBB060453 [0,1,0,0,0,0|1,0,2]=4 33 B5R0.3 CNC(=O)CCl SBB049936 [0,1,0,0,0,0|2,0,1]=4 34 B5R0.3 COC(=O)CCl SBB040686 [0,1,0,0,0,0|2,0,1]=4 35 B5R0.3 ClCC(Cl)CCl SBB060982 [0,1,0,0,0,0|0,0,2]=3 36 B5R0.3 N#CC(Cl)CCl SBB067119 [0,1,0,0,0,0|1,0,2]=4 37 B5R0.3 OC(CCl)CCl SBB060190 [0,1,0,0,0,0|1,0,2]=4 38 B5R0.4 ClCC(Cl)(Cl)Cl SBB061237 [0,1,0,0,0,0|0,0,2]=3 39 B5R0.4 ClSC(Cl)(Cl)Cl SBB058912 [0,1,0,0,0,0|1,0,1]=3 40 B5R0.4 O=S(=O)(Cl)CCl SBB066601 [0,1,0,0,0,0|2,0,1]=4 41 B5R0.5 CC(=O)C(C)Cl SBB060958 [0,1,0,0,0,0|2,0,1]=4 42 B5R0.5 CC(Br)C(Cl)Cl SBB060490 [0,1,0,0,0,0|0,1,2]=4 43 B5R0.5 CC(C)C(=O)Cl SBB060269 [0,1,0,0,0,0|2,0,1]=4 44 B5R0.5 CN(C)C(=O)Cl SBB040876 [0,1,0,0,0,0|3,0,0]=4 45 B5R0.5 CN(C)C(=S)Cl SBB085540 [0,1,0,0,0,0|3,0,0]=4 46 B5R0.5 NC(=S)C(N)=S SBB056453 [0,1,0,0,0,0|3,0,0]=4 47 B4R0.2 C\C=C\CC SBB059879 [1,1,0,0,0,0|2,0,0]=4 48 B4R0.2 ClCCCCl SBB040918 [1,1,0,0,0,0|0,0,2]=4 49 B4R0.2 Cl\C=C/CCl SBB061393 [1,1,0,0,0,0|0,0,0]=2 50 B4R0.3 ClC(Cl)(Cl)Br SBB061489 [1,1,0,0,0,0|0,0,1]=3 51 B6R0.2 O=C(Cl)CC(=O)Cl SBB060017 [0,2,0,0,0,0|1,0,0]=3 52 B6R0.4 O=C(Cl)CCCCl SBB060894 [0,2,0,0,0,0|1,0,1]=4 53 B6R0.7 ClC(Cl)C(Cl)(Cl)Cl SBB061236 [0,2,0,0,0,0|0,0,2]=4 54 B6R1.2 ClC1=CNN=C1 SBB000035 [0,1,0,1,0,0|2,0,0]=4 55 B6R1.2 ClC1=NC=CS1 SBB054425 [0,1,0,1,0,0|2,0,0]=4 56 B6R1.2 ClC1=NC=NN1 SBB019448 [0,1,0,1,0,0|2,0,0]=4