0  B15R1.913  CC(C)(C)OC(=O)Nc1ccc(cc1)Br BC000122 [0,2,0,0,0,0|2,0,0]=4
1  B15R1.913  CC(C)(C)OC(=O)Nc1ccc(cc1)I BC000175 [0,2,0,0,0,0|2,0,0]=4