0  B10R1.15  O=C(CCl)N1CCOCC1 BR020402 [0,1,0,1,0,0|2,0,0]=4
1  B10R1.15  [NH3+]CC(=O)N1CCOCC1 BR020404 [0,1,0,1,0,0|2,0,0]=4