0  B11R0.148  CCCCCCC/C=C\C(O)=O D0249 [0,0,0,0,0,0|1,0,2]=3
1  B12R0.268  O=C(Cl)CCCCCCCC(Cl)=O A0732 [0,1,0,0,0,0|2,0,1]=4
2  B11R0.3  CCCCCCCCCCC=O U0036 [1,1,0,0,0,0|0,0,0]=2
3  B11R0.3  CCCCCCCCCCCBr B0116 [1,1,0,0,0,0|0,0,1]=3