0  B15R0.164  B(CCCCCCCCCCCCC)(O)O AB23092 [1,0,0,0,0,0|1,0,1]=3
1  B14R0.392  CC\C=C\CCCCCCCCCC=O CB10426 [2,0,0,0,0,0|0,0,2]=4
2  B14R0.394  B(CCCCCCCCCCCC)(O)O AB17341 [2,0,0,0,0,0|1,0,1]=4