0 B15R0.164 B(CCCCCCCCCCCCC)(O)O AB23092 [0,0,0,0,0,0|2,0,1]=3 1 B14R0.392 CC\C=C\CCCCCCCCCC=O CB10426 [1,0,0,0,0,0|0,0,2]=3 2 B14R0.394 B(CCCCCCCCCCCC)(O)O AB17341 [1,0,0,0,0,0|2,0,1]=4