0  B16R0.303  C(CCC)=C\C=CCCCCCCCCCO DB02982 [0,0,0,0,0,0|0,0,4]=4
1  B16R0.303  CCCCCCCCCCCCCCCC=O DB03381 [0,0,0,0,0,0|0,0,2]=2
2  B17R0.43  CCCCCCCCCCCCCCCC(=O)O DB03796 [0,1,0,0,0,0|0,0,1]=2
3  B17R0.43  CCCCCC\C=C/CCCCCCCC(=O)O DB04257 [0,1,0,0,0,0|0,0,3]=4
4  B17R0.3110  [P@@H](=O)(CCCCCCCCCCC)OCCCC DB02457 [0,1,0,0,0,0|3,0,0]=4
5  B18R0.20608  CCCCCCCC[N+](C)(C)CCCCCCCC DB13970 [0,2,0,0,0,0|2,0,0]=4