0  B7R0.1  CCCCCON=O DB01612 [1,0,0,0,0,0|2,0,1]=4
1  B6R0.4  NCCCC(=O)O DB02530 [2,0,0,0,0,0|1,0,0]=3
2  B6R0.4  O=C([O-])CCCO DB01440 [2,0,0,0,0,0|1,0,1]=4
3  B6R0.4  O=C([O-])CCCO DB09072 [2,0,0,0,0,0|1,0,1]=4