0  B19R0.149  CCCCCCCCCCC#CCCCCCC(=O)O BITP1228 [0,0,0,0,0,0|0,0,2]=2
1  B19R0.149  CCCCC\C=C/C\C=C/CCCCCCCC(=O)O BIL9075 [0,0,0,0,0,0|0,0,4]=4