0  B15R2.1428  O=C1C2=C(CCC=C2)\C(O1)=C\CCC BCP09458 [0,0,0,0,0,0|0,0,4]=4
1  B15R1.30  O=C(NNCCCC)C1=CC=C(Br)C=C1 BCP16853 [0,1,1,0,0,0|2,0,0]=4