0  B12R0.5  CC\C=C/CCCCCCCCO BB31-7956 [1,0,0,0,0,0|0,0,3]=4
1  B14R0.394  N#CCCCCCCCCCCC(=O)O BB32-2948 [0,1,0,0,0,0|1,0,1]=3
2  B11R0.3  CCCCCCCCNCCN BB31-6273 [2,0,0,0,0,0|2,0,0]=4
3  B13R0.54  C=CCCCCCCCCCC(=O)O BB32-2997 [1,1,0,0,0,0|0,0,2]=4
4  B13R0.54  CCCCCCCCC\C=C\C(=O)O BB32-1603 [1,1,0,0,0,0|0,0,2]=4
5  B13R0.54  O=C(O)CCCCCCCCCCCl BB32-0804 [1,1,0,0,0,0|1,0,0]=3
6  B13R0.54  O=C(O)CCCCCCCCCCO BB31-5498 [1,1,0,0,0,0|1,0,0]=3
7  B15R1.131  CC1CCCCN1CCCNCC(=O)O BB52-9543 [0,1,0,1,0,0|2,0,0]=4
8  B15R1.504  O=C(O)CCNCCCN1CCCCC1 BB53-0560 [0,1,0,1,0,0|2,0,0]=4
9  B15R1.8958  O=C(O)CCNCCN1CCCCCC1 BB52-9590 [0,1,0,1,0,0|2,0,0]=4
10  B15R1.8958  O=C(O)CNCCCN1CCCCCC1 BB52-9940 [0,1,0,1,0,0|2,0,0]=4