0  B17R0.43  CCCCCCCCCCCCCCCC(C)=O BB31-4537 [0,0,0,0,0,0|1,0,0]=1
1  B17R0.43  C\C=C\CCCCCCCCCCCOC(C)=O BB32-1336 [0,0,0,0,0,0|2,0,2]=4
2  B16R0.274  O=C(O)CCCCCCCCCCCCCO BB31-5266 [1,0,0,0,0,0|1,0,0]=2
3  B18R0.171  COC(=O)CCCCCCCCCCCCCCBr BB31-7728 [0,1,0,0,0,0|1,0,0]=2
4  B19R0.149  CCCC\C=C/CCCCCCCCCCOC(C)=O BB32-1335 [0,2,0,0,0,0|1,0,1]=4