0  B6R0.4  CCCCC(=O)O BP1016 [0,0,1,0,0,0|1,0,0]=2
1  B6R0.4  NCCCC(=O)O BP3442 [0,0,1,0,0,0|2,0,0]=3
2  B9R1.6  O=C(O)C1=CCCNC1 BP4087 [0,2,0,0,0,0|1,0,1]=4