0  B10R0.93  O=C(O)C(Br)CC(Br)C(=O)O BB17-1995 [0,2,0,0,0,0|2,0,0]=4
1  B8R1.4  NC1=CC(=O)CCC1 BB17-0155 [1,0,0,1,0,0|2,0,0]=4
2  B10R1.63  CC1(C)CCC(=O)OC1=O BB01-8368 [0,1,0,1,0,0|2,0,0]=4