0  B4R0.1  NCC(=O)O SBB071447 [0,0,0,0,0,0|3,0,1]=4
1  B4R0.1  NCC(=O)[O-] SBB116671 [0,0,0,0,0,0|3,0,1]=4
2  B4R0.1  O=C(Br)CBr SBB040828 [0,0,0,0,0,0|4,0,0]=4
3  B4R0.1  O=C(Cl)CBr SBB051682 [0,0,0,0,0,0|4,0,0]=4
4  B4R0.1  O=C(Cl)CCl SBB040859 [0,0,0,0,0,0|4,0,0]=4
5  B4R0.1  O=C(O)CBr SBB053569 [0,0,0,0,0,0|3,0,1]=4
6  B4R0.1  [NH3+]NC(N)=O SBB060865 [0,0,0,0,0,0|3,1,0]=4
7  B3R0.2  NC(N)=O SBB008449 [1,0,0,0,0,0|2,1,0]=4
8  B5R0.1  CC(=O)N=S=O SBB059583 [0,1,0,0,0,0|2,1,0]=4
9  B5R0.3  O=CC(Br)C=O SBB069441 [0,1,0,0,0,0|3,0,0]=4
10  B5R0.4  CCS(=O)(=O)Cl SBB061401 [0,1,0,0,0,0|3,0,0]=4
11  B5R0.4  COS(C)(=O)=O SBB058203 [0,1,0,0,0,0|3,0,0]=4
12  B5R0.4  O=S(=O)(Cl)CCl SBB066601 [0,1,0,0,0,0|3,0,0]=4
13  B4R0.3  NS(N)(=O)=O SBB049643 [1,1,0,0,0,0|1,1,0]=4
14  B4R0.3  O=S(=O)(O)O SBB066031 [1,1,0,0,0,0|1,0,1]=4