0  B16R1.1576  CC1CCC(NC(=O)N(CCCl)N=O)CC1 LQ3689 [0,1,0,0,0,0|0,0,0]=1
1  B13R1.44  O=C(NCCO)NC1CCCCC1 LT5741 [2,0,0,0,0,0|1,0,0]=3