0 B29R4.8253908594 [C@@H]12CCC3=CC(=O)C=C[C@]3(C)[C@H]1C(=O)C[C@@]4(C)[C@H]2CC[C@]4(O)C(=O)CO BBC/125 [2,0,0,0,0,0|0,0,2]=4