0  B2R0.1  CNN BB32-2724 [1,0,0,0,0,0|2,0,0]=3
1  B4R0.1  C#C[C@H](C)N BB31-2680 [0,1,0,0,0,0|2,0,1]=4
2  B4R0.1  CC(N)C#N BB31-5240 [0,1,0,0,0,0|2,0,1]=4
3  B4R0.1  OCC(Cl)Cl BB31-5600 [0,1,0,0,0,0|2,0,1]=4
4  B5R0.1  CC(=O)CCBr BB31-4479 [0,2,0,0,0,0|1,0,0]=3
5  B5R0.1  CC(O)CCBr BB32-3029 [0,2,0,0,0,0|1,0,1]=4
6  B5R0.1  COCC(C)Br BB31-8127 [0,2,0,0,0,0|1,0,1]=4
7  B5R0.1  COCC(N)=O BB31-3207 [0,2,0,0,0,0|1,0,0]=3
8  B5R0.1  O=C(O)CCF BB32-2513 [0,2,0,0,0,0|0,0,0]=2
9  B5R0.1  O=C(O)\C=C\Br BB31-5400 [0,2,0,0,0,0|0,0,1]=3
10  B5R0.3  CC(CO)CBr BB31-7772 [0,2,0,0,0,0|1,0,1]=4
11  B5R0.3  CCC(=O)CN BB31-8248 [0,2,0,0,0,0|1,0,0]=3
12  B5R0.3  CO[C@@H](C)CO BB31-0453 [0,2,0,0,0,0|0,0,2]=4
13  B5R0.3  NCC(O)CCl BB31-4889 [0,2,0,0,0,0|1,0,1]=4
14  B5R0.3  O=C[C@H](O)CO BB31-6122 [0,2,0,0,0,0|0,0,1]=3
15  B5R0.5  CC(=O)C(N)=O BB32-3571 [0,2,0,0,0,0|0,0,1]=3