0 B7R1.3 Cc1ccccn1 BP22480 [0,0,0,0,0,0|2,0,0]=2 1 B7R1.3 FC1=NC=CC=C1 BP22378 [0,0,0,0,0,0|2,0,0]=2 2 B7R1.3 FC=1C=NC=CC1 BP22379 [0,0,0,0,0,0|2,0,0]=2 3 B7R1.3 [BH3-][n+]1ccccc1 BP22486 [0,0,0,0,0,0|2,0,0]=2 4 B8R1.3 BrC1=CC=C(C=C1)I BP22374 [0,1,0,0,0,0|1,0,0]=2 5 B8R1.3 CC=1C=CC(=NC1)O BP22083 [0,1,0,0,0,0|1,0,0]=2 6 B8R1.3 ClC1=NC=C(C=N1)O BP22414 [0,1,0,0,0,0|2,0,0]=3 7 B8R1.3 FC1=NC=C(C=C1)C BP22082 [0,1,0,0,0,0|2,0,0]=3 8 B8R1.4 BrC1=CC(=CC=C1)I BP22373 [0,1,0,0,0,0|1,0,0]=2 9 B8R1.4 BrC=1C=C(C=CC1)[Zn+] BP21975 [0,1,0,0,0,0|1,0,0]=2 10 B8R1.5 BrC1=C(C=CC=C1)I BP22372 [0,1,0,0,0,0|1,0,0]=2 11 B6R1.2 BrC=1C=NNC1 BP22390 [0,0,0,0,1,0|3,0,0]=4 12 B6R1.2 CC1=NNC=C1 BP22399 [0,0,0,0,1,0|3,0,0]=4 13 B6R1.2 CN1N=CC=C1 BP22412 [0,0,0,0,1,0|3,0,0]=4 14 B6R1.2 IC=1C=NNC1 BP22391 [0,0,0,0,1,0|3,0,0]=4 15 B6R1.2 N1N=CC=C1N BP22398 [0,0,0,0,1,0|3,0,0]=4 16 B9R1.1 BrC1=NC=C(C=C1)C=O BP22440 [0,2,0,0,0,0|1,0,1]=4 17 B9R1.1 BrC1=NC=C(C=C1)OC BP22094 [0,2,0,0,0,0|1,0,0]=3 18 B9R1.1 C(C)C=1C=CC(=NC1)C BP22488 [0,2,0,0,0,0|2,0,0]=4 19 B9R1.1 C(C)C=1C=CC(=NC1)C BP22540 [0,2,0,0,0,0|2,0,0]=4 20 B9R1.2 C(#C)C=1C=C(N)C=CC1 BP22436 [0,2,0,0,0,0|1,0,0]=3 21 B9R1.6 C1(=CC=CC=C1)B(O)O BP20145 [0,2,0,0,0,0|0,0,0]=2 22 B9R1.6 C[C@@H](c1ccncc1)O BP22558 [0,2,0,0,0,0|1,0,0]=3 23 B9R1.6 C[C@H](O)C1=CC=CC=C1 BP22543 [0,2,0,0,0,0|0,0,0]=2 24 B9R1.6 C[C@H](c1ccccc1)O BP22542 [0,2,0,0,0,0|0,0,0]=2 25 B9R1.6 C[C@H](c1ccncc1)O BP22557 [0,2,0,0,0,0|1,0,0]=3 26 B9R1.6 N1=C(C=CC=C1)[C@@H](C)O BP22555 [0,2,0,0,0,0|1,0,0]=3 27 B9R1.6 N1=C(C=CC=C1)[C@H](C)O BP22556 [0,2,0,0,0,0|1,0,0]=3 28 B9R1.6 N1=CC(=CC=C1)B(O)O BP20136 [0,2,0,0,0,0|1,0,0]=3 29 B9R1.6 N1=CC(=CC=C1)B(O)O BP21984 [0,2,0,0,0,0|1,0,0]=3 30 B9R1.6 N1=CC=C(C=C1)B(O)O BP20148 [0,2,0,0,0,0|1,0,0]=3 31 B9R1.6 N1=CN=CC(=C1)B(O)O BP20180 [0,2,0,0,0,0|2,0,0]=4 32 B9R1.69 BrC1=C(N)C=CC(=C1)F BP22342 [0,2,0,0,0,0|1,0,0]=3 33 B9R1.69 BrC=1C(=NC(=CC1)C)C BP22099 [0,2,0,0,0,0|2,0,0]=4 34 B9R1.3 BrC1=C(C=CC=C1Cl)Cl BP22370 [0,2,0,0,0,0|1,0,0]=3 35 B9R1.3 FC1=C(C=CC=C1F)O BP22402 [0,2,0,0,0,0|0,0,0]=2 36 B9R1.34 BrC=1C=C(C=C(C1)Cl)O BP22408 [0,2,0,0,0,0|0,0,0]=2 37 B9R1.34 OC1=CC(OC(=C1)C)=O BP22386 [0,2,0,0,0,0|1,0,0]=3 38 B9R1.34 c1c(cc(cc1Br)Br)Cl BP22393 [0,2,0,0,0,0|1,0,0]=3