0  B3R0.2  C=C(C)Br BB0272402 [0,0,0,0,0,0|4,0,0]=4
1  B3R0.2  C=[N+](C)C BB0263006 [0,0,0,0,0,0|3,0,0]=3
2  B3R0.2  NC(N)=O BB0269740 [0,0,0,0,0,0|3,0,0]=3
3  B4R0.1  C\C(N)=N\O BB0241915 [0,1,0,0,0,0|3,0,0]=4
4  B4R0.1  NCC(=O)O BB0265974 [0,1,0,0,0,0|2,0,0]=3
5  B4R0.3  NS(N)(=O)=O BB0260582 [0,1,0,0,0,0|2,0,1]=4
6  B3R0.1  O=CC=O BB0268084 [1,1,0,0,0,0|1,0,1]=4
7  B5R1.2  O=C1COC1 BB0263332 [0,1,0,1,0,0|2,0,0]=4