0  B18R0.221  CCCCCCCC\C=C/CCCCCCCCBr BB31-6280 [1,0,0,0,0,0|1,0,1]=3
1  B20R0.2931  CCCCCCCCCCCCCCCC(O)CC(=O)O BB31-3644 [0,1,0,0,0,0|0,0,2]=3
2  B20R1.3309  CCCCCCCCCCCCCCC1CCC(=O)O1 BB31-4900 [0,0,0,1,0,0|0,0,2]=3
3  B17R0.43  CCCCCCCCCCCCCCCC(C)=O BB31-4537 [2,0,0,0,0,0|1,0,0]=3
4  B21R0.81  O=C(O)CCCCCCCCCCCCCCCCCCBr BB31-8673 [0,2,0,0,0,0|0,0,2]=4