0  B3R0.1  O=CC=O BB0268084 [0,1,0,0,0,0|3,0,0]=4
1  B3R0.2  C=C(C)Br BB0272402 [0,1,0,0,0,0|2,1,0]=4
2  B3R0.2  C=[N+](C)C BB0263006 [0,1,0,0,0,0|3,0,0]=4
3  B3R0.2  NC(N)=O BB0269740 [0,1,0,0,0,0|3,0,0]=4