0  B3R0.2  F[Sb](F)F A0988 [0,1,0,0,0,0|3,0,0]=4
1  B3R0.2  NC(N)=N G0058 [0,1,0,0,0,0|2,0,1]=4
2  B3R0.2  NC([NH3+])=N G0040 [0,1,0,0,0,0|2,0,1]=4