0  B3R0.1  O=CC=O BB0268084 [0,1,0,0,0,0|0,0,1]=2
1  B3R0.2  C=C(C)Br BB0272402 [0,1,0,0,0,0|2,0,1]=4
2  B3R0.2  C=[N+](C)C BB0263006 [0,1,0,0,0,0|3,0,0]=4
3  B3R0.2  NC(N)=O BB0269740 [0,1,0,0,0,0|1,0,1]=3
4  B4R0.1  NCC(=O)O BB0265974 [0,2,0,0,0,0|0,0,2]=4
5  B4R0.3  NS(N)(=O)=O BB0260582 [0,2,0,0,0,0|1,0,0]=3