0  B4R0.3  O=S(=O)(F)Cl M016-6-02 [0,0,0,0,0,0|3,0,0]=3
1  B4R0.3  O=S(=O)(F)F M016-2-04 [0,0,0,0,0,0|3,0,0]=3
2  B3R0.2  O=C(F)F 2116-2-02 [1,0,0,0,0,0|3,0,0]=4
3  B3R0.2  O=S(F)F M016-2-03 [1,0,0,0,0,0|3,0,0]=4
4  B2R0.1  O=C=S 6166-0-01 [2,0,0,0,0,0|1,1,0]=4
5  B2R0.1  O=S=O M016-0-01 [2,0,0,0,0,0|1,0,0]=3