0  B4R0.3  NS(N)(=O)=O BB0260582 [0,0,0,0,0,0|3,0,1]=4
1  B3R0.2  NC(N)=O BB0269740 [1,0,0,0,0,0|3,0,0]=4
2  B4R0.1  NCC(=O)O BB0265974 [1,1,0,0,0,0|2,0,0]=4