0  B3R0.2  CS(=O)[O-] BB12-1172 [0,0,0,0,0,0|4,0,0]=4
1  B3R0.2  N[13C](N)=O BB54-5648 [0,0,0,0,0,0|4,0,0]=4
2  B2R0.1  F[Xe]F BB54-5276 [1,0,0,0,0,0|1,2,0]=4
3  B1R0.1  [13CH3]I BB54-5275 [2,0,0,0,0,0|1,1,0]=4