0  B3R0.2  C=C(C)Br BB0272402 [0,0,0,0,0,0|3,1,0]=4
1  B3R0.2  C=[N+](C)C BB0263006 [0,0,0,0,0,0|4,0,0]=4
2  B3R0.2  NC(N)=O BB0269740 [0,0,0,0,0,0|4,0,0]=4