0  B3R0.2  N=C(N)N STR00188 [0,0,0,0,0,0|4,0,0]=4
1  B3R0.2  NC(N)=O STR00449 [0,0,0,0,0,0|4,0,0]=4
2  B5R0.5  O=C([O-])C(Cl)Cl AS-58721 [0,2,0,0,0,0|2,0,0]=4