0  B20R0.90  CCCCCC[C@H](O)C\C=C/CCCCCCCC(=O)[O-] A11440 [1,0,0,0,0,0|0,0,1]=2
1  B19R0.149  CCCCC\C=C\C\C=C\CCCCCCCC(=O)O D75304 [2,0,0,0,0,0|0,0,2]=4