0  B15R0.414  NCCC[C@H](NC(=O)CCC(=O)O)C(=O)O C03415 [2,0,0,0,0,0|0,0,0]=2
1  B15R0.414  O=CCC[C@H](NC(=O)CCC(=O)O)C(=O)O C05932 [2,0,0,0,0,0|1,0,1]=4