0  B20R0.17440  CCCCC\C=C/C=C/[C@@H](O)CCCCCCCC(=O)O DB07302 [1,0,0,0,0,0|0,0,0]=1
1  B19R0.149  CCCCCC\C=C/CCCCCCCCCC(=O)O DB04801 [2,0,0,0,0,0|0,0,2]=4
2  B19R0.149  CCCCC\C=C/C=C/CCCCCCCCC(=O)O DB04746 [2,0,0,0,0,0|0,0,0]=2
3  B19R0.149  CCCCC\C=C/C\C=C/CCCCCCCC(=O)O DB14104 [2,0,0,0,0,0|0,0,2]=4