0  B10R0.3  C=C(C)CCC[C@H](C)CCO R1283 [0,0,0,0,0,0|0,0,4]=4
1  B10R1.245  CC1=CCCC(C)=C1C=O D5786 [1,0,0,1,0,0|0,0,2]=4