0  B17R0.43  CCCCCCCCCCCCCCCC(=O)O DB03796 [1,0,0,0,0,0|0,0,1]=2
1  B17R0.43  CCCCCC\C=C/CCCCCCCC(=O)O DB04257 [1,0,0,0,0,0|0,0,3]=4
2  B16R0.303  CCCCCCCCCCCCCCCC=O DB03381 [2,0,0,0,0,0|0,0,1]=3
3  B16R0.303  CCCCCCCCCCCCCCCCO DB09494 [2,0,0,0,0,0|0,0,2]=4
4  B16R0.302  [C@@H](O)(CCCCCCCCCCC)CC(=O)O DB02767 [0,0,0,0,2,0|0,0,2]=4